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PHYSICS 103L
LABORATORY EXPERIMENTS
EXPERIMENT – 9
YOUNG’S MODULUS - Report
Name: Adar Turan
Section: 11
Table ( 15 points):
Aluminum Mass (g) Force (N) F = m.g Width (m) a Thickness (m) h Length (m) L Δy (m) E (N/m^2 ) EAVE 60g
10x10-^3 3x10-^3 500x10-^3
5.05×10^- 7
110g
160g
210g
260g
Aluminum Mass (g) Force (N) F = m.g Width (m) a Thickness (m) h Length (m) L Δy (m) E (N/m^2 ) EAVE 60g
10x10-^3 2x10-^3 500x10-^3
1.96×10^-
110g
160g
210g
260g
Draw F - Δy graph for each one. (20 points)
260g
Steel Mass (g) Force (N) F = m.g Width (m) a Thickness (m) h Length (m) L Δy (m) E (N/m^2 ) EAVE 60g
20x10-^3 1.5x10-^3 500x10-^3
1.58×10^- 7
110g
160g
210g
260g
Draw F - Δy graph for each one. (20 points)
Results: (15 points +15 points if you choose your own sentences) The experiment successfully determined the Young’s Modulus values for Aluminum and Steel samples with varying dimensions. For Aluminum, the 3 mm thickness sample had an average Young’s Modulus of N/m^2, while the 2 mm thickness sample showed a lower average of 1.96×10^ 7 N/m due to the reduced cross-sectional area. For Steel, the 15 mm width sample had an average Young’s Modulus of 1.37×10^7 N/m^2 , whereas the 20 mm width sample displayed a slightly higher average of 1.58×10^7N/m^2. These results align with theoretical expectations, demonstrating that changes in cross-sectional dimensions influence the stiffness of the material. Minor discrepancies may have resulted from experimental errors, such as inaccuracies in measuring displacements or imperfections in the materials.
