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A comprehensive guide to understanding nominal and effective interest rates in engineering economics. It covers various aspects, including the types of interest rates, parameter values, and their application in different scenarios. The document also includes examples and formulas to illustrate the concepts and calculations involved. It is a valuable resource for students and professionals in engineering and finance.
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2/25/ Prepared by: Engr. Emy Barrioquinto
ENGINEERING ECONOMICS E N G R. E M Y B A R R I O Q U I N T O
2/25/ Prepared by: Engr. Emy Barrioquinto
For example situation period compounding PP = CP Monthly (12) Monthly (12) PP < CP Quarterly (4) Monthly (12) PP > CP Monthly (12) Quarterly (4)
2/25/ MONTHLY DEPOSIT OF 6,000.00 FOR 3 YEARS, WITH INTEREST RATE OF 8% COMPOUNDED MONTHLY. What is the Future worth?
2/25/ 6,000 MONTHLY DEPOSIT FOR 3 YEARS, WITH INTEREST RATE OF 8% PER YEAR COMPOUNDED Quarterly.
(1) PP = 12, CP = 4, IP = 1/ (2) Nominal interest rate of 8% - > interest rate per compounding: 0.08/4 = 0. (3) Base amount = 6,000 / (1/3) = 18, (4) n: 3 years * 4 compounding period = 12 Solve future value using this notation 18,000 (F/A, 0.02%, 12)
2/25/ Prepared by: Mr. Juan P. Dela Cruz
If a nominal interest rate is quoted and the number of compounding periods per year and number of years are known, any problem involving future amounts, annual, or present equivalent values can be calculated by straightforward use of equations 𝐹 = 𝑃 (1+ 𝑖) 𝑁 (Single payment compound amount factor) and 𝑖 = (1 + 𝑟 𝑀 ) 𝑀 − 1, respectively 2/25/ Prepared by: Engr. Emy Barrioquinto
2/25/ Prepared by: Engr. Emy Barrioquinto
When there is more than one compounded interest period per year, the formulas and tables for uniform series and gradient series can be used as long as there is a cash flow at the end of each interest period 2/25/ Prepared by: Engr. Emy Barrioquinto EFFECTIVE INTEREST RATES IN GRADIENT SERIES
Certain operating savings are expected to be 0 at the end of the first six months (period 1 with 6 months), to be $1,000 at the end of the second six months, and to increase by $1,000 at the end of each six-month period thereafter, for a total of four years. Find the equivalent uniform amount, A, at the end of each of the eight six-month periods if the nominal interest rate is 20% compounded semiannually. 2/25/ Prepared by: Engr. Emy Barrioquinto Note that gradient is treated like Annuity
2/25/ Prepared by: Engr. Emy Barrioquinto Maria wants to save for a new laptop and plans to deposit $500 at the end of each quarter into a savings account that earns a nominal annual interest rate of 8% compounded monthly. She will make these deposits for 3 years. How much will Maria have in her account at the end of 3 years? 𝒊 = 𝟏 + 𝒓 ( 𝑰 𝑷 ) ( 𝑷 𝑷 ) 𝑰 𝑷 − 𝟏
2/25/ Prepared by: Engr. Emy Barrioquinto Which yield better return: a) 9% compounded daily or b) 9.1% compounded monthly?