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Synthetic Division: Performing Quotient and Remainder Calculation, Lecture notes of Mathematics

The synthetic division method for dividing polynomials. It provides an example of how to write the problem, perform the division step by step, and read the quotient and remainder. The document also includes several practice problems for students to try.

Typology: Lecture notes

2021/2022

Uploaded on 08/05/2022

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Synthetic Division Review
To divide synthetically:
1. The divisor must be a binomial that can be written xc. Only c is used
from the divisor.
2. The dividend must be written with powers of the variable in descending
order. Only coefficients of the dividend are used and zero (0) is used as a
placeholder for any missing variable term or constant.
The following is an example that demonstrates how to write the problem to
divide synthetically.
(x3 + 4x2 – 8) / (x + 4)
(1x3 + 4x2 + 0x – 8)
x + 4 is the divisor -4 1 4 0 -8 Dividend
-4 0 0
Divisor 1 0 0 -8 (-8) Remainder
Quotient
We now outline the actual sequence of steps involved when using synthetic
division to solve (2x3 + 3x2 – 4x + 8) / (x + 3)
First, show the divisor and the dividend:
-3 2 3 -4 8
Next, “bring down” the first coefficient of the dividend:
-3 2 3 -4 8
________
2
pf3

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Synthetic Division Review

To divide synthetically:

  1. The divisor must be a binomial that can be written xc. Only c is used from the divisor.
  2. The dividend must be written with powers of the variable in descending order. Only coefficients of the dividend are used and zero (0) is used as a placeholder for any missing variable term or constant.

The following is an example that demonstrates how to write the problem to divide synthetically.

(x 3 + 4x 2 – 8) / (x + 4)

(1x 3 + 4x 2 + 0x – 8) x + 4 is the divisor -4 1 4 0 -8 ⇐ Dividend ⇑ -4 0 0 Divisor 1 0 0 -8 ⇐ (-8) Remainder ⇑ ⇑ ⇑ Quotient

We now outline the actual sequence of steps involved when using synthetic division to solve (2x 3 + 3x 2 – 4x + 8) / (x + 3)

First, show the divisor and the dividend:

Next, “bring down” the first coefficient of the dividend:

⇓⇓⇓⇓ ________

Step 1 -3 2 3 -4 8 Step 2 Multiply (-3) (2) ⇓⇓⇓⇓ -6______ ⇐ Product of (-3) (2) ⇓ ⇒ 2 - ⇑ Step 3 Add (3) + (-6)

Continue following a similar pattern:

-3 2 3 -4 8 Step 2 Step 1 ⇓⇓⇓⇓ -6 9__ ⇐⇐⇐⇐ Product of (-3) (-3) Multiply ⇓ 2 -3 5 (-3) (-3) ⇓⇒⇒⇑ ⇑ Step 3 Add (-4) + (9)

Continue:

Step 1 -3 2 3 -4 8 Step 2 Multiply (-3) (5) ⇓ -6 9 -15 ⇐ Product of (-3) (5) ⇓ 2 3 5 - ⇓⇒⇒⇒⇒ ⇑ ⇑ Step 3 Add (8) + (-15)

The quotient is read using the numbers in the final row as coefficients and by lowering the highest exponential power of the original dividend by one. Q(x) = 2x 2 + 3x + 5

The remainder is the last digit in the final row: R(x) = - The remainder is expressed as a numerator with the divisor as the denominator. Example: -7 / (x + 3)

The final answer is: 2x 2 + 3x + 5 – 7/(x + 3)