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State Minimization - Digital System Design - Lecture Slides, Slides of Digital Systems Design

The digital system design, is very helpful series of lecture slides, which made programming an easy task. The major points in these laboratory assignment are:State Minimization, Reduction in States, Distinguishing States, Corresponding Table Cell, Distinguishable Outputs, Final State Reduction Table, Effect of Outputs, Modified Rule, Input Transitions, Moore Fsm Example

Typology: Slides

2012/2013

Uploaded on 04/24/2013

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Download State Minimization - Digital System Design - Lecture Slides and more Slides Digital Systems Design in PDF only on Docsity!

State Minimization

 Two Equivalent FSMs

 A sensor example: detect and don’t repeat

 Two equivalent ways to design the FSM – one has

fewer states than the other

 Distinguishing States (2)

 Let d(q,x) be the state the follows state q on input x

 Example: d(A,1) = B, and d(A,0) = A

 Rule 2 : two states A

and A

are distinguishable if

 d(A

1

,1) and d(A

2

,1) are distinguishable, or

 d(A

1

,0) and d(A

2

,0) are distinguishable

A/
S=
B/
S=
S=
C/
S=
S=
S=
D/
S=
S=

B 

C 

D 

A B C

 Testing States A and C

 d(A,0)=A and d(C,0)=D

 We know nothing about A and D at this point

 d(A,1)=B and d(C,1)=C

 B and C are known to be distinguishable  so are A

and C

 Place a mark in the corresponding table cell

A/
S=
B/
S=
S=
C/
S=
S=
S=
D/
S=
S=

B 

C  

D 

A B C

 Testing States C and D

 d(C,0)=D and d(D,0)=A

 Looks promising since D and A are the same ….

 d(C,1)=C and d(D,1)=B

 B and C are known to be distinguishable  so are C

and D

 Place a mark in the corresponding table cell

A/
S=
B/
S=
S=
C/
S=
S=
S=
D/
S=
S=

B 

C  

D  

A B C

 Resulting FSM

 Testing State A

 d(A,0)=B and d(B,0)=D  distinguishable!

 d(A,0)=B and d(E,0)=B, and

 d(A,1)=D and d(E,1)=C  don’t know yet …

B 

C  

D  

E  

F   

A B C D E

(A,E)

x=

A/1 B/

x=

D/0 F/

x=

x=

x=

x=

C/

x=0 x=

x=

E/

x=

x=

x=

 Testing State B

 d(B,0)=D and d(E,0)=B  distinguishable!

B 

C  

D  

E   

F   

A B C D E

(A,E)

x=

A/1 B/

x=

D/0 F/

x=

x=

x=

x=

C/

x=0 x=

x=

E/

x=

x=

x=

 Testing State C (2)

 d(C,0)=D and d(F,0)=C, and

 d(C,1)=A and d(F,1)=D  distinguishable!

B 

C  

D  

E   

F    

A B C D E

(C,D)^ (A,E)

x=

A/1 B/

x=

D/0 F/

x=

x=

x=

x=

C/

x=0 x=

x=

E/

x=

x=

x=

 Testing State D

 d(D,0)=D and d(F,0)=C, and

 d(D,1)=E and d(F,1)=D  distinguishable!

B 

C  

D  

E   

F     

A B C D E

(C,D)^ (A,E)

x=

A/1 B/

x=

D/0 F/

x=

x=

x=

x=

C/

x=0 x=

x=

E/

x=

x=

x=

 Resulting Minimal FSM

 The Effect of the Outputs  Consider the two FSMs:

 The only difference is in the output of states C

This FSM cannot be

 - 00/  How can you automate the reduction in states? 
  • Sense= - 10/ - Sense= - Sense= - 11/ - Sense= - Sense= - Sense= - 01/ - Sense=
  • Sense= - 00/ - Sense= - 10/ - Sense= - Sense= - 11/ - Sense=0 Sense= - Sense= - A/  States A and D are equivalent
    • S= - B/ - S= - S= - C/ - S= - S= - S= - D/ - S=
  • S= - S= - A/ - S= - B/ - S= - S= - C/ - S= - S=
    • A/1 B/ - x=
      • D/0 F/
  • x=1 x= - x= - x= - x= - x=0, - x= and E
    • A/1 B/ - x=
      • D/0 F/
  • x= - x= - x= - x= - C/ - x=0 x= - x= - E/ - x= - x= - x= - x= - A/1 B/ - x= - D/0 F/ - x= - x= - x= - x= - C/ - x=0 x= - x= - E/ - x= - x= - x=

 Final State Reduction Table

A B
G
F
C
E
D

B 

C 

D   

E  

F    

G     

A B C D E F

(B,C)

(B,E), (C,E)

(D,G)

 Minimal FSM

 A  F

 B  C  E

 D  G

A B
G
F
C
E
D
A
B
D