Solution Manual of Fox and McDonalds Introduction to Fluid Mechanics 9th edition, Summaries of Mechanics

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M =12.6 lb M =0.391 slug

M 204 × 14.7lbf in^2

⋅ 144 in

⋅^2

ft 2

× × 0.834 ⋅ ft 3 1

× lb R⋅ ft lbf⋅

× 1

R

⋅ × 32.2 lb ft⋅ s^2 ⋅lbf

M = V ⋅ρ p V⋅ RN2 ⋅T

Hence =

V π V =0.834 ft 3 4

 ⋅ft

2 = × × 4.25⋅ft

V π 4

where V is the tank volume = ⋅ D 2 ⋅L

ρ M V

p =ρ ⋅ RN2⋅T and =

The governing equation is the ideal gas equation

RN2 55.16 ft lbf⋅ (Table A.6) lb R⋅

T =( 59 + 460 ) R⋅ T =519 R = ⋅

D =6 in⋅ L =4.25 ft⋅ p =204 atm⋅

The given or available data is:

Solution

Find: Mass of nitrogen

Given: Data on nitrogen tank

Problem 1.

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