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An in-depth look at solving rational inequalities using cases and intervals. It covers the rules for solving inequalities, examples of solving rational inequalities using cases, and an alternative method using intervals. The document also includes a number line diagram and a graph to help visualize the solutions.
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r a t i o n a l f u n c t i o n s
MHF4U: Advanced Functions
Part 1: Simple Inequalities
J. Garvin
Slide 1/
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Rational inequalities can be solved using similar techniques for solving polynomial inequalities: cases or intervals. Recall the rules for solving inequalities. Rules for Solving Inequalities
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Example
Solve
x − 2
−4 using cases.
Since x − 2 6 = 0, there are two cases to consider.
Case 1: x − 2 > 0, or x > 2.
3 x − 2
3 > −4(x − 2) 3 > − 4 x + 8 − 5 > − 4 x 5 4 <^ x
J. Garvin — Solving Rational Inequalities Slide 3/
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Consider the two intervals on a number line.
Since x > 2 is common, it is a solution to the inequality.
J. Garvin — Solving Rational Inequalities Slide 4/
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Case 2: x − 2 < 0, or x < 2.
3 x − 2
3 < −4(x − 2) 3 < − 4 x + 8 − 5 < − 4 x 5 4 >^ x
J. Garvin — Solving Rational InequalitiesSlide 5/
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Consider the two intervals on a number line.
Since x < 54 is common, it is a solution to the inequality.
The solution, then, is
x − 2
−4 on
A graph confirms these intervals.
J. Garvin — Solving Rational InequalitiesSlide 6/
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While this method works, it can be tedious and difficult to follow at times.
J. Garvin — Solving Rational InequalitiesSlide 7/
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Example
Solve x^2 − 6 x + 8 2 x^2 + 5x − 3 ≤ 0 using intervals.
Begin by factoring the numerator and denominator to determine any vertical asymptotes or x-intercepts that define intervals. x^2 − 6 x + 8 2 x^2 + 5x − 3
(x − 4)(x − 2) (2x − 1)(x + 3)
There are vertical asymptotes at x = −3 and x = 12 , and x-intercepts at x = 2 and x = 4. J. Garvin — Solving Rational InequalitiesSlide 8/
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Set up a table with five intervals.
Interval (−∞, −3)
x − 4 0 1 3 5 Sign of P(x) + − + − +
The rational function is less than zero on two intervals, and equal to zero at the two roots.
Therefore, x^2 − 6 x + 8 2 x^2 + 5x − 3 ≤ 0 on
Again, graphing confirms the intervals.
J. Garvin — Solving Rational Inequalities Slide 9/
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It is hard to see the detail between the two x-intercepts at this scale, so zoom in for clarity.
J. Garvin — Solving Rational Inequalities Slide 10/
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J. Garvin — Solving Rational InequalitiesSlide 11/
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J. Garvin — Solving Rational InequalitiesSlide 12/