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Solving Rational Inequalities: Techniques and Examples, Exams of Algebra

An in-depth look at solving rational inequalities using cases and intervals. It covers the rules for solving inequalities, examples of solving rational inequalities using cases, and an alternative method using intervals. The document also includes a number line diagram and a graph to help visualize the solutions.

Typology: Exams

2021/2022

Uploaded on 08/05/2022

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rational functions
MHF4U: Advanced Functions
Solving Rational Inequalities
Part 1: Simple Inequalities
J. Garvin
Slide 1/12
rational functions
Rational Inequalities
Rational inequalities can be solved using similar techniques
for solving polynomial inequalities: cases or intervals.
Recall the rules for solving inequalities.
Rules for Solving Inequalities
The same value may be added to, or subtracted from,
both sides of an inequality.
Each side of an inequality may be multiplied, or divided,
by the same positive value.
Each side of an inequality may be multiplied, or divided,
by the same negative value if the inequality is reversed.
If each side of an inequality has the same sign, the
reciprocal of each side may be taken if the inequality is
reversed.
J. Garvin Solving Rational Inequalities
Slide 2/12
rational functions
Solving Rational Inequalities Using Cases
Example
Solve 3
x2>4 using cases.
Since x26= 0, there are two cases to consider.
Case 1: x2>0, or x>2.
3
x2>4
3>4(x2)
3>4x+ 8
5>4x
5
4<x
J. Garvin Solving Rational Inequalities
Slide 3/12
rational functions
Solving Rational Inequalities Using Cases
Consider the two intervals on a number line.
Since x>2 is common, it is a solution to the inequality.
J. Garvin Solving Rational Inequalities
Slide 4/12
rational functions
Solving Rational Inequalities Using Cases
Case 2: x2<0, or x<2.
3
x2>4
3<4(x2)
3<4x+ 8
5<4x
5
4>x
J. Garvin Solving Rational Inequalities
Slide 5/12
rational functions
Solving Rational Inequalities Using Cases
Consider the two intervals on a number line.
Since x<5
4is common, it is a solution to the inequality.
The solution, then, is 3
x2>4 on −∞,5
4(2,).
A graph confirms these intervals.
J. Garvin Solving Rational Inequalities
Slide 6/12
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r a t i o n a l f u n c t i o n s

MHF4U: Advanced Functions

Solving Rational Inequalities

Part 1: Simple Inequalities

J. Garvin

Slide 1/

r a t i o n a l f u n c t i o n s

Rational Inequalities

Rational inequalities can be solved using similar techniques for solving polynomial inequalities: cases or intervals. Recall the rules for solving inequalities. Rules for Solving Inequalities

  • (^) The same value may be added to, or subtracted from, both sides of an inequality.
  • (^) Each side of an inequality may be multiplied, or divided, by the same positive value.
  • (^) Each side of an inequality may be multiplied, or divided, by the same negative value if the inequality is reversed.
  • If each side of an inequality has the same sign, the reciprocal of each side may be taken if the inequality is reversed. J. Garvin — Solving Rational InequalitiesSlide 2/

r a t i o n a l f u n c t i o n s

Solving Rational Inequalities Using Cases

Example

Solve

x − 2

−4 using cases.

Since x − 2 6 = 0, there are two cases to consider.

Case 1: x − 2 > 0, or x > 2.

3 x − 2

3 > −4(x − 2) 3 > − 4 x + 8 − 5 > − 4 x 5 4 <^ x

J. Garvin — Solving Rational Inequalities Slide 3/

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Solving Rational Inequalities Using Cases

Consider the two intervals on a number line.

Since x > 2 is common, it is a solution to the inequality.

J. Garvin — Solving Rational Inequalities Slide 4/

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Solving Rational Inequalities Using Cases

Case 2: x − 2 < 0, or x < 2.

3 x − 2

3 < −4(x − 2) 3 < − 4 x + 8 − 5 < − 4 x 5 4 >^ x

J. Garvin — Solving Rational InequalitiesSlide 5/

r a t i o n a l f u n c t i o n s

Solving Rational Inequalities Using Cases

Consider the two intervals on a number line.

Since x < 54 is common, it is a solution to the inequality.

The solution, then, is

x − 2

−4 on

A graph confirms these intervals.

J. Garvin — Solving Rational InequalitiesSlide 6/

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Solving Rational Inequalities Using Cases

While this method works, it can be tedious and difficult to follow at times.

J. Garvin — Solving Rational InequalitiesSlide 7/

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Solving Rational Inequalities Using Intervals

Example

Solve x^2 − 6 x + 8 2 x^2 + 5x − 3 ≤ 0 using intervals.

Begin by factoring the numerator and denominator to determine any vertical asymptotes or x-intercepts that define intervals. x^2 − 6 x + 8 2 x^2 + 5x − 3

(x − 4)(x − 2) (2x − 1)(x + 3)

There are vertical asymptotes at x = −3 and x = 12 , and x-intercepts at x = 2 and x = 4. J. Garvin — Solving Rational InequalitiesSlide 8/

r a t i o n a l f u n c t i o n s

Solving Rational Inequalities Using Intervals

Set up a table with five intervals.

Interval (−∞, −3)

2 ,^2

x − 4 0 1 3 5 Sign of P(x) + − + − +

The rational function is less than zero on two intervals, and equal to zero at the two roots.

Therefore, x^2 − 6 x + 8 2 x^2 + 5x − 3 ≤ 0 on

∪ [2, 4].

Again, graphing confirms the intervals.

J. Garvin — Solving Rational Inequalities Slide 9/

r a t i o n a l f u n c t i o n s

Solving Rational Inequalities Using Cases

It is hard to see the detail between the two x-intercepts at this scale, so zoom in for clarity.

J. Garvin — Solving Rational Inequalities Slide 10/

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Solving Rational Inequalities Using Cases

J. Garvin — Solving Rational InequalitiesSlide 11/

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Questions?

J. Garvin — Solving Rational InequalitiesSlide 12/