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Photodetectors - Optoelectronic Engineering - Lecture Notes | EEE 265, Study notes of Electrical and Electronics Engineering

Material Type: Notes; Professor: Tatro; Class: Optoelectronic Engineering; Subject: Electrical & Electronic Engr; University: California State University - Sacramento; Term: Unknown 1989;

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2009/2010

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Chapter 6
Photodetectors
H-Alpha Solar
Blogeko
GreenAndGoldenEnergy.com.au
Section 6.1 Solar Energy Spectrum
Photovoltaic devices or solar cells convert the incident solar
radiation energy into electrical energy.
The intensity of the radiation emitted from the sun has a spectrum
that resembles a black body radiation at a temperature of about
6,000 K.
Incident photons are absorbed to photogenerate charge carriers that
pass through an external load to do electrical work .
0
Black body radiation at 6000 K
AM0
AM1.5
0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.
0
0
0.5
1.0
1.5
2.0
2.5
Wavelength (
μ
m)
Spectral
Intensity
dW cm
-2
(
μ
m)
-1
or
kW m
-2
(
μ
m)
-1
The spectrum of the solar energy repr esented as spectral
intensity (I
λ
) vs wavelength above th e earth's atmosphere
(AM0 radiation) and at the earth's surface (AM1.5
radiation). Black body radiation at 6000 K is shown for
comparison (After H.J. Möller, Semiconductors for Solar
Cells, Artech House Press, Boston, 1993, p.10)
From S.O. Kasap, Optoelectronics and Photonics: Principles and Practices (Prentice
Hall)
Figure 6.1
Space = Air Mass Zero
Earth’s surface = AM 1.5
Solar Energy Spectrum
The earth’s atmosphere absorbs and scatters the solar radiation
depending on the wavelength. Thus the space value (AM0) is not
available at the earth’s surface.
Iλδλ is the intensity in a small interval δλ. Integration over the
whole spectrum give the total intensity I.
Light intensity variation with wavelength is typically represented
by intensity per unit wavelength, called spectral intensity Iλ.
This total intensity I gives the total power flow through a unit area
perpendicular to the direction of the sun. This quantity is called
solar constant or air-mass zero (AM0) radiation = 1,353 W/m2.
Solar Energy Spectrum
The actual intensity spectrum on the earth’s surface depends on the
absorption and scattering effect of the atmosphere. The
atmosphere’s composition (pollutants, airborne particulates, and so
on) and on the path length through the atmosphere.
Note on the next figure the effects of angle of the device with
respect to the sun and diffuse (cloudy) versus clear sky.
All of these effects depend on the spectral wavelength. Indeed
laser spectroscopy and atmospheric interferometrydepends on this
effect.
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Chapter 6

Photodetectors

H-Alpha Solar

Blogeko

GreenAndGoldenEnergy.com.au

Section 6.1 Solar Energy Spectrum

Photovoltaic devices or solar cells convert the incident solar

radiation energy into electrical energy.

The intensity of the radiation emitted from the sun has a spectrum

that resembles a black body radiation at a temperature of about

6,000 K.

Incident photons are absorbed to photogenerate charge carriers that

pass through an external load to do electrical work.

0

Black body radiation at 6000 K AM

AM1.

0.2 0.4^ 0.6^ 0.8^ 1.0 1.2 1.4^ 1.6 1.8^ 2.

0

Wavelength (μm)

Spectral Intensity dW cm-2^ (μm) -

or kW m-2^ (μm) -

The spectrum of the solar energy represented as spectral intensity ( I λ) vs wavelength above the earth's atmosphere (AM0 radiation) and at the earth's surface (AM1. radiation). Black body radiation at 6000 K is shown for comparison (After H.J. Möller, Semiconductors for Solar Cells , Artech House Press, Boston, 1993, p.10)

From S.O. Kasap, Optoelectronics and Photonics: Principles and Practices (Prentice Hall)

Figure 6.

Space = Air Mass Zero

Earth’s surface = AM 1.

Solar Energy Spectrum

The earth’s atmosphere absorbs and scatters the solar radiation

depending on the wavelength. Thus the space value (AM0) is not

available at the earth’s surface.

Iλ δλ is the intensity in a small interval δλ. Integration over the

whole spectrum give the total intensity I.

Light intensity variation with wavelength is typically represented

by intensity per unit wavelength, called spectral intensity Iλ.

This total intensity I gives the total power flow through a unit area

perpendicular to the direction of the sun. This quantity is called

solar constant or air-mass zero (AM0) radiation = 1,353 W/m

2

Solar Energy Spectrum

The actual intensity spectrum on the earth’s surface depends on the

absorption and scattering effect of the atmosphere. The

atmosphere’s composition (pollutants, airborne particulates, and so

on) and on the path length through the atmosphere.

Note on the next figure the effects of angle of the device with

respect to the sun and diffuse (cloudy) versus clear sky.

All of these effects depend on the spectral wavelength. Indeed

laser spectroscopy and atmospheric interferometry depends on this

effect.

Direct Diffuse

(a) Illustration of the effect of the angle of incidence θ on the ray path length and the

definitions of AM0, AM1 and AM(sec θ). The angle α between the sun beam and the horizon

is the solar latitude (b) Scattering reduces the intensity and gives rise to a diffused radiation

Atmosphere

AM

AM

θ

AM(sec θ)

h 0^ h

α

(a) (b)

α

Tilted PV device

Earth

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

Figure 6.2 Example 6.1.1 on page 256 Solar energy conversion

Suppose a family house in a sunny geographic location consumes a

daily average electrical power of 500 W.

Let the annual average solar intensity incident per day (daylight

intensity averaged for 24 hour day) is 6 kW hours/m

2

. This is about

7 hours of direct sunlight per day.

Lastly let the efficiency of the solar cell be about 15%. Space borne

solar cells achieve about 30% efficiency at a cost of about

$100,000/m^2. The 15% efficient cell is around $500/m2.

What is the required solar cell area to supply this required power?

Energy per house

Incident solar energy per unit area × Efficiency

Area =

2

sec (500 )(86, 400 )

3600sec (6000 )( )(0.15)

W day

W hour

m day hour

= ⋅

2 =13.3 m

Example 6.1.1 on page 256 Solar energy conversion

So the space capable system would cost about 1.5 million dollars,

but would receive/convert more power by about a factor of 4.

The terrestrial installed solar cell at 15% would cost about $6,700.

Obviously, this solar system cannot match the peak power

requirements. Storage batteries and energy transfer to the power

grid add cost and complexity.

The payback period for a solar device is between 3 and 30 years

with 5 years considered the current average.

Section 6.2 Photovoltaic Device Principles

Consider a pn junction with a very narrow and more heavily doped

n-region. The illumination is through the thin n-side.

Neutral n -region Neutral p -region

W

Eo

Voc

Medium λ

Long λ

Depletion region

Drift Diffusion

Finger electrode

Back electrode

A n A p

Le

The principle of operation of the solar cell (exaggerated features to highlight principles)

Lh

Short λ

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

The depletion region W extends

primarily into the p-side. As in any

pn junction there is a built-in field

(and voltage) E 0.

The necessary current collection

electrodes attached to the n-side must

allow illumination to enter the device

and still result in a small series

resistance. Finger electrodes are the

device structure commonly used.

Finger electrodes

p

n

Bus electrode for current collection

Finger electrodes on the surface of a solar cell reduce the series resistance

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

Figure 6.

Monocrystaline

Polycrystaline

Photovoltaic Device Principles

A thin antireflection coating on the surface reduces reflections

from the surface and allows more light to enter the device.

Neutral n -region Neutral p -region

W

Eo

Voc

Medium λ

Long λ

Depletion region

Drift Diffusion

Finger electrode

Back electrode

A n A p

Le

The principle of operation of the solar cell (exaggerated features to highlight principles)

Lh

Short λ

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

EHPs generated in the depletion

regions are immediately separated by

the built-in field to the bulk regions

where the charges can form an

external current.

For long wavelength photons, only

those EHPs created within a minority

carrier diffusion length of the

depletion region contribute to an

external current.

pn Junction Photovoltaic I-V Characteristics

By the text’s definitions used for the solar cell, the load resistor

appears to be delivering power since the current is not in accordance to

the power sign convention.

The author solved this notation dilemma by using the relationship

as negative resistance.

Thus we can find a specific (-R) that solves for the Vand I

required. The load line approach solves this problem graphically.

V

I

R

V

I (mA)

0.2 0.4 0.

0

Voc

Isc = – Iph

V

The Load Line for R = 30 ž ( I-V for the load)

I-V for a solar cell under an illumination of 600 Wm-2.

Operating Point

Slope = – 1/ R

P

I

(a) When a solar cell drives a load R , R has the same voltage as the solar cell but the current through it is in the opposite direction to the convention that current flows from high to low potential. (b) The current I ′ and voltage V ′ in the circuit of (a) can be found from a load line construction. Point P is the operating point ( I ′, V ′). The load line is for R = 30 ž.

Light I

R

V

I

(a) (b)

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

Figure 6.

pn Junction Photovoltaic I-V Characteristics

Another approach is the solve the P = VI equation and take the

derivative for maximum power. Let the ideality factor n = 1.

ph 0 exp^ k TB^1 e

V P I V I V V I

⎡ (^) ⎛ ⎞ ⎤ = ⋅ = − + ⋅ (^) ⎢ (^) ⎜ ⎟−⎥ ⎢⎣ ⎝ ⎠ ⎥⎦

max max (^0) ph 0 exp (^) k TB (^1 0) max exp k TB e b e

dP V e V I I I V dV k T

Now define the thermal voltage as V t = k BT/e

max max max 0

exp 1 exp

ph

t t t

V V I

V

V V V I

⎢ ⎜ ⎟ −^ ⎥+^ ⎜ ⎟ ⎜ ⎟=

max max

0

1 exp 1

ph

t t

V V I

V V I

⎜ +^ ⎟ ⎜ ⎟=^ +

max max

0

exp see homework 6.

ph

t t

V V I

V V I

pn Junction Photovoltaic I-V Characteristics

This last relationship can be solved by trial and error over the limited

voltages (typically 0.4 < Vmax < 0.6 for silicon) of a solar cell.

The current I ph will depend on the illumination and I 0 will be parameter

for the particular pn junction solar cell.

max max

0

1 exp 1

ph

t t

V V I

V V I

⎜ +^ ⎟ ⎜ ⎟=^ +

Since the open circuit voltage is the maximum voltage possible, and

short circuit current Isc is the maximum current possible, the

unachievable maximum power = Isc V oc.

The fill factor is a measure of how close to the maximum power is a

particular operating point.

m m

sc oc

I V FF I V

=

Problem 6.3 A solar cell driving a resistive load

A solar cell of area A = 4 cm^2 in connected to drive a load R.

Illumination = 600 W/m^2 behavior is shown in the figure.

Let the load R = 20 Ω and the intensity change to 1 kW/m^2.

What are the current and voltage in the circuit?

V

I (mA)

0.2 0.4 0.

0

Voc

  • Iph

V

The Load Line for( I-V for the load) R = 30 ž

I-V for a solar cell under an illumination of 600 Wm-2. Operating Point

Slope = – 1/ R

P

I

The solar cell is now used under an illumination of 1 kW/m^2. The short circuit

current Isc must be scaled by a factor of 1,000/600 = 1.67.

V ′ (^) V

I (mA)

0.4 0.

0

The load line for R = 20 ž ( I-V for the load)

I-V for a solar cell under an illumination of 1000 Wm -.

P

I

M

The figure shows the load line for R = 20 Ω.

The corresponding current I’= 22.5 mA.

The voltage V’ = 0.45 V.

Problem 6.3 A solar cell driving a resistive load

What is the power delivered to the load?

Pin = (Light Intensity)(Surface Area)

What is the efficiency of the solar cell in this circuit?

The efficiency η is given by

' ' 3 Poutput I V (22.5 10 A )(0.45 V ) 10.1 mW

− = = × =

4 2 2 2

2 10 in (1, 000^ W^ )(4^ m ) m cm

P cm

100%

out

in

P

P

η = ×

= 0.4 W

= × =

Problem 6.4 Open Circuit voltage and illumination

A solar cell under an illumination of 100W/m^2.

Short circuit current Isc = 50 mA Open circuit voltage Voc = 0.55 V.

What is Isc and Voc when the light intensity is halved?

Example 6.3.2 showed (We will assume the ideality constant n = 1.)

2 2 1 1

oc oc t ln

Intensity V V nV Intensity

2 2 1 1

sc sc

Intensity I I Intensity

2 2 1 1

sc sc

I

I I mA I

⎝ ⎠ ⎝^ ⎠

= 25 mA

2 2 1 1

ln 0.55 (0.0259) ln 2

oc oc t

I

V V V

I

⎝ ⎠ ⎝^ ⎠

= 0.55 − 0.018 =0.53 V

Section 6.4 Series Resistance and Equivalent Circuit

Practical devices can deviate substantially from the ideal pn

junction solar cell behavior considered so far.

The finger electrodes introduce an effective series resistance Rs

into the photovoltaic circuit. Small thin electrodes (the better for

light to pass through) further increase this series resistance.

A fraction of the current can flow through the crystal surfaces

(edges of the device) or through grain boundaries in

polycrystalline devices. This is represented as a shunt (or parallel)

resistance Rp.

Neutral n -region

Neutral p -region

Finger electrode

Back electrode

Depletion region

R (^) L

R (^) s

R (^) p

Series and shunt resistances and various fates of photegenerated EHPs.

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

Figure 6.

A

Iph

R p V R^ L

Iph I

Id

Solar cell Load

B

R s

The equivalent circuit of a solar cell

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

Figure 6.

I (mA)

V

0 0

0.2 0.4 0.

5

10

Vo c

I (^) s c

Rs = 0

Rs = 20 Ω

Rs = 50 Ω

I (^) p h

The series resistance broadens the I-V curve and reduces the maximum available power and hence the overall efficiency of the solar cell. The example is a Si solar cell with n ≈ 1.5 and Io ≈ 3 × 10 -6^ mA. Illumination is such that the photocurrent I (^) ph = 10 mA.

© 1999 S.O. Kasap, Optoelectronics (Prentice Hall)

Figure 6.11 Effect of Series and parallel resistance to the operating point. Problem 6.6 Series Connected Solar Cells

Consider two identical solar cells subject to the same illumination Iph = 10 mA.

I 0 = 25 x 10-6^ mA

RS = 20 Ω Ideality constant n = 1

Find the maximum power that can be delivered by two cells in series.

In this case there are two RS = 20 Ω in series and two pn junctions is series.

Thus the current is

Let I be the current through both and Vd the voltage across one pn junction then

(2 ) 2

s d

V I R V

0 exp^1

d ph t

V I I I V

⎡ ⎛ ⎞ ⎤ = − + (^) ⎢ ⎜ ⎟−⎥ ⎢⎣ (^) ⎝ ⎠ ⎥⎦

0

(2 ) exp 1 2

s ph t

V I R I I V

⎡ ⎛ − ⎞ ⎤ = − + (^) ⎢ ⎜ ⎟−⎥ ⎢⎣ (^) ⎝ ⎠ ⎥⎦

0

(2 ) exp 2

s ph t

V I R I I V

⎛ − ⎞ ≈ − + (^) ⎜ ⎟ ⎝ ⎠

Solar One Project – Mojave, California

First generation directly heated steam for the generator for power in

Second generation heated molten salts then transferred the heat to a

steam generator for power.

SEGS Project – Kramer Junction, California

SEGS – solar-thermal-electric generating system still in operation.

The parabolic reflectors heat oil which is used to generate steam for a

conventional turbine generator since 1985.

Stirling Engines

These are closed cycle regenerative gas engines.

Dish concentrators by Stirling Engine Systems.

R.D. McConnell, J. Thompson, National Renewable Energy Laboratory

Concentrator Photovoltaic Systems

Spectrolab has teamed up with the Arizona Public Service (APS) to develop and

deploy the first grid-connected concentrator system that utilizes Spectrolab’s

GaInP/GaAs/Ge triple-junction solar cells.

This module is operational at the APS Solar Test and Research (STAR) facility in

Tempe, Arizona under 500-sun concentration and has been operational since April

Concentrator Cell on Cooling Plate

Arionza Public Service (^) Solar Cells Materials, Devices and Efficiencies

Concentrator PV relies on gathering light over some area and then

focusing it down onto a photovoltaic cell.

Since the net area density of the photovoltaic material is much

smaller than for flat-plate PV, its is economically possible to use

newer generation higher efficiency cells.

A three junction cell made by Boeing-Spectrolab Inc. claims

efficiencies of 39% at 236 suns.

There are thermal management issues with these concentrator PV

systems and continued research is addressing this issue.

R.D. McConnell, J. Thompson, National Renewable Energy Laboratory

Best Research-Cell Efficiencies Dye Solar Cell

Swiss Federal Institute of Technology

Dye Sensitized Nanocrystalline Solar Cell (DYSC)

Swiss Federal Institute of Technology

Solar Flight!

HELIOS prototype close-up on the lakebed, August 18, 2001, Photo Tom Tschida;

NASA Dryden Flight Research Center

End of Chapter 6