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Modul 1 Yehuda Pratama Analisi Teknik Pengukuran
Typology: Lab Reports
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TME 142 - Praktikum Fisika
Vol
t
, Vol=πr
2
t; S
Q
Jawabam:
∂Vol
∂π
=r
2
t
∂Vol
∂r
=π2rt
∂Vol
∂t
=πr
2
Vol
=√(r
2
t)
2
(Sπ)
2
+(π2rt)
2
(Sr)
2
+(πr
2
2
(St)
2
∂Vol
t
2
Q
t
2
r
2
t
2
Sπ
2
π2rt
2
Sr
2
πr
2
2
St
2
2
2
2
St
2
2. δ=
F.L
3
3E.I
δ
∂δ
3
∂δ
2
∂δ
3
2
∂δ
3
2
𝛿
3
2
2
2
2
2
3
2
2
2
3
2
2
2
3. I=m(v-v
0
I
∂m
=(v-v
0
∂v
= m
0(m
2
r
3
3
(mgt)
(m
2
r
3
2
∂r
0(m
2
r
3
4
(mgt)
(m
2
r
3
2
𝑉
gt(m
2
r
3
) − 2 𝑚(mgt)
(m
2
r
3
2
2
Sm
2
mt(m
2
r
3
) − 0 (mgt)
(m
2
r
3
2
2
Sg
2
mg(m
2
r
3
) − 0 (mgt)
(m
2
r
3
2
2
St
2
0(m
2
r
3
3
(mgt)
(m
2
r
3
2
2
2
0(m
2
r
3
4
(mgt)
(m
2
r
3
2
2
Sr
2
𝑃
𝑡
𝑊
𝑃
2
2
2
2
t
∂t
t
2
W
t
2
2
2
2
2
2
t
2
2
St
2
𝑦
𝑦
∂m
= g
∂g
= m
𝐹
2
2
2
2
𝑦
𝑦
𝐹
𝑦
2
2
2
2
2
2
2
2
Pengukuran
ke s (cm) t (s) t
2
s. t
k = 6 ∑ s = 18,96 ∑ t = 120,
∑ t
2
∑ s. t =
a=
2
b=
2
S = 0,18 t – 0,
t = 2,15 maka, S = - 0,
t = 53,46 maka, S = 9,
