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Heat Transfer I: Fin/Sirip Conduction Exercises, Exams of Heat and Mass Transfer

Universitas 17 Agustus 1945 Surabaya (UNTAGS)Heat and Mass Transfer

4. Block mesin sebuah motor bakar tersusun atas 5 sirip yang menyatu dengan block engine berbentuk silinder dan terbuat dari bahan tungsten (Kungsten= 174 W/m?K), ukran dri sirip H = 0,18 m, t= 0,008 m, r = 0,028 m dan r2= 0,048 m dan kocfisen konveksi (h= 40 W/m2?K) jika temperatur luar mesin Tb= 130+87=217?C dan temperatur udara luar 30?C. Tentukan laju perpindahan panas total setelah dipasang sirip dan perpindahan panasnya jika tanpa sirip

Typology: Exams

2016/2017

Available from 12/26/2021

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MATAKULIAH : PERPINDAHAN PANAS I
MODEL TUGAS : EAS
MATERI : Konduksi pada Fin/sirip
AWAL TUGAS : 21 Desember 2017
AKHIR TUGAS : 25 Desember 2017
NAMA : Misbakul irsat
NBI/KLAS : 142140462/R
1.
Diket : - N= 20 sirip + 02 = 22 Sirip
- L= 0,2 m
- t = 0,008m
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MATAKULIAH : PERPINDAHAN PANAS I

MODEL TUGAS : EAS

MATERI : Konduksi pada Fin/sirip

AWAL TUGAS : 21 Desember 2017

AKHIR TUGAS : 25 Desember 2017

NAMA : Misbakul irsat

NBI/KLAS : 142140462 /R

Diket : - N= 20 sirip + 02 = 22 Sirip

  • L= 0,2 m
  • t = 0, 008 m
  • w=0,2 m

- K

tungten

= 174 W/m

o

K

  • h= 40 W/m

2o

K

- T

b

o

C= 460,

O

K

- T

u

o

C= 303,

o

K

  • r 1

= 0, 28 m

  • r

2

= 0, 048 m

  • H =0,18 m

Asirip =(2 x Luas alas)+ (keliling alas x tinggi)

= 0,0612 m

2

P = (AB+BC+CD+AD) = 0,104 m

2

A

tot

= N.Asirip+ 2π r 1

(H-Nt)

= 3 ,03 m

2

m =

h. P

K. A

T − 30

{cosh_. m_ ( 1 − x )+ 0,0447.sinh_. m_ ( 1 − x ) ; x = 1

T = 30 +

o

C =298,

o

( Temperatur diujung batang )

h. As ( T

ujung − Tu

hAs ( Tb − Tu )

  1. Diket : - N= 100 sirip + 02 = 1 02 sirip
    • P = 0,2 m
    • t= 0, 008 m
    • r1=0, 028 m
    • r2=0,048 m

- K

tungsten

= 174 W/m

o

K

  • h= 40 W/m

2o

K

- T

b

o

C= 460,

O

K

- T

u

o

C= 303,

o

K

  • H= 0, 18 m

As=π.p (r 1

+r 2

) + π.p (r 1

2

+r 2

2

As=3,14. 0, 2 (0,02 8 +0,0 48 )+ 3,14. 0,2 (0,0 28

2

2

As= 0,628 (0, 32 ) +0,628 (0,00 30 )

As= 0, 2009 + 0,00 18

As= 0, 20284 m

2

A

tot

= N.As+ 2(w.t).(H-N.t)

A

tot

A

tot

A

tot

= 24,876 m

2

m =

h. P

K. A

T − 30

{cosh_. m_ ( 1 − x )+ 0,0447.sinh_. m_ ( 1 − x ) ; x = 1

T = 30 +

=25,9 °C =298,15 ° K ( Temperatur diujung batang )

h. As ( T

ujung − Tu

hAs ( Tb − Tu )

ξ =

L +

t

h

K .t

Dengan adanya sirip laju perpindahan panas

Q tot = h. A tot

[

N. A

F

A

tot

. ( 1 − η

s

]

. ( Tb − Tu )

Q tot = 40_._ 3,

[

]

Q tot =¿ 14 981,

Dengan tanpa sirip laju perpindahan panas konveksi adalah

Q

tanpa sirip

= h (2.π.r 1

.H) (Tb-Tu)

Q

tanpa sirip

Q

tanpa sirip

= 207,993W

t

L

Diket : - N= 75 sirip+ 02 = 79 sirip

  • L= 0,15 m
  • t = 0,0 08 m
  • r 1

= 0,0028 m

  • w= 0,2 m

- K

tungsten

= 1 74 W/m

o

K

  • h= 4 0 W/m

2o

K

- T

b

o

C= 4 6 0,

O

K

- T

u

o

C= 303,

o

K

  • H= 0, 18 m

A

S

= 2w

√

L

2

  • 1 / 4 t

2

A

S

2

2

A

S

❑

A

S

= 0,06 m

2

Diket : - N= 5 sirip

  • L= 0,02 m
  • t= 0,008 m
  • K= 177 W/m

o

K

  • h= 40 W/m

2o

K

- T

b

o

C=4 6 0,

O

K

- T

u

o

C= 303,

o

K

  • H= 0,18 m
  • r 1

= 0,028 m

  • r 2

= 0,048 m

As= 2.π (r 2

2

-r 1

2

)+ 2πr 2

t

As= 2.3,14 (0,

2

2

)+ 2. 3,14. 0,048. 0,008 = 0,0119 m

2

As= 6,28 (0,002304 – 0,000784) + 0,

As= 0,0119 m

2

A

total

= N.As + 2.π.r 1

.(H-N.t)

A

total

A

total

A

total

= 0,0846 m

2

Dari gambar 4-10 efisiensi sirip (ŋ s

) ≈ 0,96, pada

r

2

t

r

1

ξ =( L +

t )

h

K .t

Dengan adanya sirip laju perpindahan panas

Q tot = h. A tot

[

N. A

F

A

tot

. ( 1 − η

s

]

. ( Tb − Tu )

Q tot =40.0,

[

]

Q tot =450,5 W

Dengan tanpa sirip laju perpindahan panas konveksi adalah

Q

tanpa sirip

= h (2.π.r

1

.H) (Tb-Tu)

Q

tanpa sirip

Q

tanpa sirip

Q

tanpa sirip

= 173,45 W