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Indeterminate Forms Questions for exam
Typology: Exams
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Some Important results :
(^1 2 ) 1 x 1 x x x .......
2 3 4 x x x Log 1 x x ....... 2 3 4
3 5 7 x x x Sinx x ....... 3 5 7
2 4 6 x x x Cosx 1 ....... 2 4 6
3 5 x 2x Tanx x ....... 3 15
2 3 4 x x^ x^ x e 1 x ....... 2 3 4
1 2 x x^ 11x (1 x) e 1 ....... 2 24
b a
log(ab) log a l og b; log(a / b) log a l og b; log a b loga; log a 1
1 x
x 0
Lim 1 x e
; log1 0; log e 1; log ; log0 ; e ; e 0;
2
x 0 5
Sinx x x 6 Lim x
x 0 2
xCosx Log(1 x) Lim x
1 2
3 x (^0) x (^2)
x Tanx Lim
(e 1)
1 x
x 0
(1 x) e Lim x
x 0
Sinx Lim x
x
x 0
e 1 Lim x
x 0 2
1 Cosx Lim x
x x
x 0
a b Lim x
2
x
x 0
xe Log(1 x) Lim x
3 x 0
x Sinx Lim Tan x
x 1
logx Lim (^) x 1
2 x 0
Tanx x Lim x Tanx
x Sinx
x 0
e e Lim x Sinx
1 x
x 0 2
(1 x) e ex 2 Lim x
1 2
6 x 0
SinxSin x x Lim x
1
2 x 0
SinxSin x Lim x
2 2
x 0 4
Sin x x Lim x
x
x 0
1 x e Log e Lim Tanx x
x (^2)
Cosx Lim
x 2
^
x 0
logx Lim Cotx
x 0
logSin2x Lim logSinx
2
x 0
log log(1 x ) Lim log logCosx
x (^2)
Lim Secx 1 Sinx
x 0
Lim x logSinx
x 0
Cotx Lim(Cosx)
x
x
a Lim 1 x
2
x 0
Cot x Lim(Cosx)
Lim x Sin x
1 Log(1 x) Lim x x
1 x
x 0
Sinx Lim x
(^12) x
x 0
Tanx Lim x
x 0
Cotx x Lim x
x (^0)
Co sec x Cotx Lim x
x (^0)
Lim Sinx logx
x 0
Lim x logx
x (^2)
Lim Secx Tanx ^
x x (^0)
Lim e 1 x
may be equal to ‘1’.
x x
x 0
.
1 x
x 0
Lim(Cosx)
1 (1 x)
x 0
Lim(x)
(^12) x
x (^0)
Sinx Lim x
1 x
x
Logx Lim x
1
1 x
x
Lim Tan x 2
1 Logx
x 0
Lim(Co sec x)
x (^1)
x Lim(1 x)Tan 2
Tan 2x
4
x
Lim (Tanx) ^
x (^2)
Lim 1 Sinx Tanx ^
x
Lim xTan 1 x
3
2 x
x Logx Lim 1 x x