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During the study of discrete mathematics, I found this course very informative and applicable.The main points in these lecture slides are:Direct Proof, Vacuous Proof, Trivial Proof, Indirect Proof, Constructive Proof, Non-constructive Existence Proof, Set Identity, Symmetric Difference, Power Set, Membership Table, Proof by Cases
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Prove each problem using the indicated technique: a) Direct Proof : Prove that the square of an even number is an even number. b) Vacuous Proof : Show that all positive integers such that n^ =log 2 n are roots of a polynomial of the form (^) ax^3^ + bx^2 + cx + d = 0 (where a, b, c, and d are fixed integers). c) Trivial Proof : Show that all prime numbers are of the form 3k or 3k+1 or 3k-1 where k is an integer. d) Indirect Proof : n is even if and only if 5 n^2 + 2 is even (n is an integer). e) Proof by Cases : Show that min(a, min(b, c))=min(min(a, b), c)) when a, b, and c are real numbers. f) Constructive Proof : For every three natural numbers x, y, z larger than 1 (x, y, z > 1), there is some natural number larger than all x, y, z such that it is not divisible by x or y or z. g) Non-constructive Existence Proof : Consider two numbers: 2! 1 05 00 + 15 and 2! 1 05 00 + 16. Prove that at least one of them is not a perfect square.
Let R, S, and T be sets. Consider the following set identity: R! ( S " T ) =( R! S ) " ( R! T ) a) Prove the identity using a membership table. b) Prove the identity by showing that R! ( S " T )is a subset of ( R! S ) " ( R! T ), and ( R! S ) " ( R! T ) is a subset of R! ( S " T ).
3 ) Let A, B, and C be sets. a) Prove that A! B = A! B. b) Prove that ( A! B )! C = ( A! C )! ( B! C ). c) The symmetric difference of A and B, denoted by A! B , is the set containing those elements in either A or B, but not in both A and B. Show that A! B = ( A " B ) !( B " A ). d) Is symmetric difference associative, that is, does it follow that A! ( B! C ) = ( A! B )! C?
a) Let A = { !, {! }}. What is its power set, PA? b) What is PA! A? c) If B and C are two sets, prove or disprove the identity, B! C = C! B.