Chapter02-Electric Circuit Analysis and Design Donald A Naem-Electrical Circuital Analysis-Solution Manual, Exercises of Electronic Circuits Analysis

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Electronic Circuit Analysis and Design, 2™ edition Solutions Manual Chapter 2 Exercise Solutions B21 Raloonm 5 a ip(peak) = aco = lldmA b Va(max) = 24412 = 26 V vy = Msinwd = 12.6 —_ 6 wh =sin7 (33) =3.7 *, By symmetry, wt2 = 180 — 31.7 = 148.27 = (#534) x L0O% => 32.4% vy = T5sin (2x600) ¥, ve FRO o Reto 78 FOV, (6050 x 10-4) E23 v= 120sin(27601}, Ve =O.7. R= 25 kT Full-wave recefier Tums rano 1: 2 3 ve = 6, Vu = 120-07 = 119.9 ¥ Ve = 119.3 = 100 = 19.3 ¥ Vm 8 119.3 DFAT, — WENN2S x 10 \19.3) C=206x 10% = WEx 10 CH= 6 eP SoC = v, = 50sin (QrG0t), ¥, = 07, R= 19kR Pull-wave cectifier ca Ym 5 0a) ~ FFRV, ~ 3(60)(10 » 20°)(2) C= 2.025 « 107? = 20.25 x 1075 > C= 03 AP E2S Using Eq. (2-10) fe _ fea a wats Er j= = 0.589 369° 10 < Vas S14 V, Ve 86 20< Rp < 100 5.8 ia) = 28 = wT = 0.28 A, fr(min) = Too = 0.056 A Ip{max) =