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Calculation methods for engineers, Schemes and Mind Maps of Calculus for Engineers

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Typology: Schemes and Mind Maps

2022/2023

Uploaded on 04/03/2025

emre-unal
emre-unal 🇹🇷

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Q1:
a)
Using augmented form
10 2 −1 25
−3 −6 2 −60
1 1 5 −20
Step 1:
Multiply the first row by -3/10 and substract from the second line,
Multiply the first row by 1/10 and substract from the third line,
10 2 −1 25
0 −5.4 1.7 −52.5
0 0.8 5.1 −22.5
Step 2:
Multiply the second row by 0.8/-5.4 and substract from the third line,
10 2 −1 25
0 −5.4 1.7 −52.5
0 0 5.352 −30.278
x3 = (-30.278/5.352) = -5.657
x2 = (-52.5-1.7*(-5.657))/(-5.4) = 7.941
x1 = (25-2*7.941-(-1)*(-5.657))/10 = 0.346
pf3
pf4
pf5

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a) Using augmented form ൥

Step 1: Multiply the first row by -3/10 and substract from the second line, Multiply the first row by 1/10 and substract from the third line, ൥

Step 2: Multiply the second row by 0.8/-5.4 and substract from the third line, ൥

x3 = (-30.278/5.352) = -5. x2 = (-52.5-1.7(-5.657))/(-5.4) = 7. x1 = (25-27.941-(-1)*(-5.657))/10 = 0.

b) [A] = ൥

൩ b = ൭

Construct the upper and lower triangular matrices. [U] = ൥

൩ [L] = ൥

[L] {d}={b} and [U] {x}={d} ൥

d1 = 25, d2 = -52.5, d=-30. {d} = ൭

[U] = ൥

x3 = -5.656, x2 = 7.942, x1 = 0. {x} = ൭

c) [L] [U] ቌ

(𝑎ି ଵ^ )ଵଵ

(𝑎ି ଵ^ )ଶଵ

(𝑎ି ଵ^ )ଷଵ

൱ [L]{d}={I 1 } = ൭

[L] [U] ቌ

(𝑎ି ଵ^ )ଵଶ

(𝑎ି ଵ^ )ଶଶ

(𝑎ି ଵ^ )ଷଶ

൱ [L]{d}={I 2 } = ൭

[L] [U] ቌ

(𝑎ି ଵ^ )ଵଷ

(𝑎ି ଵ^ )ଶଷ

(𝑎ି ଵ^ )ଷଷ

൱ [L]{d}={I 3 } = ൭

[U]{x}={d} ቌ

(𝑎ି ଵ^ )ଵଵ

(𝑎ି ଵ^ )ଶଵ

(𝑎ି ଵ^ )ଷଵ

[U]{x}={d} ቌ

(𝑎ି ଵ^ )ଵଶ

(𝑎ି ଵ^ )ଶଶ

(𝑎ି ଵ^ )ଷଶ

[U]{x}={d} ቌ

(𝑎ି ଵ^ )ଵଷ

(𝑎ି ଵ^ )ଶଷ

(𝑎ି ଵ^ )ଷଷ

[A]-1^ = ൥

a) Using augmented form ൥

Step 1: Multiply the first row by -3/10 and substract from the second line, Multiply the first row by 1/10 and substract from the third line, ൥

Step 2: Multiply the second row by 0.8/-5.4 and substract from the third line, ൥

x3 = (-43.75/26.666) = -1. x2 = (0-12.5(-1.640666))/(30) = 0. x1 = (50-15(-1.640666)-20*(0.6836108))/8 = 7. b) [A] = ൥

൩ b = ൭

൱ [U] = ൥

൩ [L] = ൥

[L] {d}={b} and [U] {x}={d} ൥

d1 = 50, d2 = 0, d=-43.75; {d} = ൭

[U] = ൥

x3 = -1.6406, x2= 0.6836, x1=7. {x} = ൭